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The output of logic gate is '1' when all its inputs are at logic '0' The gate is (A) NAND/EX-OR (B) NOR/EX-OR (C) AND/EX-NOR (D) NOR/EX-NOR

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The answer is (D)

If we take two input A and B, and corresponding output Y then for nor gate Y = complement of (A+B)  ;for ex-nor gate Y= A.B + complement of(A.B)

The above two relation showing always Y =1 for A=0,B=0.

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