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Two port networks are connected in cascade. The parameters of the network are obtained by multiplying in individual

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Two port networks are connected in cascade. The parameters of the network are obtained by multiplying in individual ABCD parameter matrix

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A passive 2-port network is in a steady state, compared to its input, the steady state output can never offer   (a) Higher voltage (b) Lower impedance (c) Greater power (d) Better regulation

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Condition for reciprocity and symmetry of a two port network are respectively  A) Z11=Z22 and Z12=Z21 B) Z11=Z12 and Z22=Z21 C) Z12=Z21 and Z11=Z22 D) Z22=Z21 and Z22=Z12

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For a two port symmetric bilateral network, if A= 3Ω and B = 1Ω, the value of parameter C will be  (A) 4s (B) 6s (C) 8s (D) 16s

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A two port network having a 6 dB loss will give  (A) an output power which is one - quarter of the input power (B) an output power which is one - half of the input power (C) an output voltage which is 0.707 of the input voltage. (D) an output power which is 0.707 of the input power.

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For a two port network to be reciprocal:  (A) Z11= Z22 (B) Y21 = Y21 (C) h21 = h22 (D) AD-BC = 0 

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The power consumed by a balanced 3-ph load is measured by two-wattmeter method. The meter readings are 8 kW and 4 kW. The power factor of the load is (A) zero (B) 0.5 (C) between zero and 0.5 (D) between 0.5 and unity

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In a static over-current relay, inverse time characteristics are obtained by   (a) A differentiating circuit (b) An integrating circuit (c) A transistor amplifier (d) A transistor switch

asked Apr 10, 2018 in Electrical Engineering by Shimroz123
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While measuring power in a three phase load by two wattmeter method, the reading of two wattmeter are equal and opposite, when (a) load is balanced (b) power factor is unity (c) phase angle is between 60° to 90° (d) the load is purely inductive 

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In the measurement of three phase power by two wattmeter method, if the two wattmeter readings are equal then power factor of the circuit is  (A) 0.8 lag (B) Unity (C) 0.8 lead (D) Zero 

asked Apr 5, 2018 in Electrical Engineering by Shimroz123
1 answer 28 views

Two light bulbs are connected in series across a 120 V battery. Bulb 1 uses 40 W of power and Bulb 2 uses 20 W of power. If bulb 1 alone is connected to the 120 V source, then it will consume (A) 90 W (B) 80 W (C) 60 W (D) 180 W

asked Apr 25, 2018 in Electrical Engineering by Shimroz123

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