A current of 4 amperes flowing for 45 minutes deposits 1.062 gm of metal at cathode. Calculate the equivalent weight of the metal. (Given 1 Faraday = 96500 C)

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Given:

c : 4 amperes

t : 45 minutes : 45 x 60 = 2700 seconds

w : 1.062 gm

1 Faraday : 96500 C

To calculate: Eq. Weight (CE)

According to Faraday’s first law:

w = z c t Therefore,

z = w / ct

z = 1.062 / 4 x 2700

z = 1.062 / 10800 E.C.E.

z = 0.00009833 g/c

Now, C.E. = 96500 x E.C.E.

C. E. = 96500 x 0.00009833

C.E. = 9.4888 gm

c : 4 amperes

t : 45 minutes : 45 x 60 = 2700 seconds

w : 1.062 gm

1 Faraday : 96500 C

To calculate: Eq. Weight (CE)

According to Faraday’s first law:

w = z c t Therefore,

z = w / ct

z = 1.062 / 4 x 2700

z = 1.062 / 10800 E.C.E.

z = 0.00009833 g/c

Now, C.E. = 96500 x E.C.E.

C. E. = 96500 x 0.00009833

C.E. = 9.4888 gm