6 views
asked by
Explain full wave bridged rectifier with the help of circuit diagram and input output waveform.

Your answer

Thanks for your contribution. Feel free to answer this question. Please avoid short answer. Your answer is most welcome. Be genuine.

Upload image or document:

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.

1 Answer

0 votes
answered by

image

1. In positive half cycle (0 to Π): The end A of the secondary winding becomes positive and end B negative. This makes diode D1 and D4 forward biased while diode D2 and D3 are reverse biased. These two diodes will be in series through the load RL. The conventional current direction is as follows. A – D1 – RL – D4 – B This makes load voltage polarities as shown in the fig above. 


2. In negative half cycle (Π to 2Π). The end B is positive and A is negative. This makes diode D2 and D3 forward biased and diode D1 and D4 is reverse biased. The conventional current through diode D2 and D3 when it is conducting is as follows. 

B – D2 – RL – D3 – A 

image

Welcome to Q&A site for electrical and electronics engineering discussion for diploma, B.E./B.Tech, M.E./M.Tech, & PhD study.
If you have a new question please ask in English.
If you want to help this community answer these questions.

...