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The maximum demand of consumer is 2 kW and his daily energy consumption is 20 units. Its Load Factor is (1) 10.15% (2) 41.6 % (3) 50 % (4) 60% 

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1 Answer

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Total maximum demand of energy in a day = 2kw*24= 48 units

Consumer consumption is 20 units .

Load factor = (number of units utilizing)/(total max. demand) 

    = 20/48 = 41.6%

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